Expressing Linear Orders Requires Exponential-Size DNNFs

17 Jul 2018 · Ronald de Haan ·

We show that any DNNF circuit that expresses the set of linear orders over a set of $n$ candidates must be of size $2^{\Omega(n)}$. Moreover, we show that there exist DNNF circuits of size $2^{O(n)}$ expressing linear orders over $n$ candidates.

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